What volume of carbonmonoxide at 2 atm and `273^(@)C` is required in order to produce 5.6 grams of metal by the reduction of ferric oxide? 

Explanation

Reduction of ferric acid oxide with carbonomoxide give iron metal
`Fe_(2)O_(3)+3CO to 3CO_(2)+2Fe`
2 moles of Fe=3 moles of CO
56 grams of Fe =33.6 L of CO at STP
5.6 grams of Fe=3.36 lit of CO at STP
The volume of CO required at STP=33.6 L
STP conditions `" Given conditions"`
`P_(1)=1atm" "P_(2)=2atm`
`T_(1)=273K" "T_(2)=2 xx 273K`
`V_(1)=3.36L" "V_(2)=?`
`V_(2)=(P_(1)V_(1))/(T_(1)) xx T_(2)/P_(2)=(1 xx 3.36 xx 2 xx 273)/(273 xx 2)=3.36L`