What is the volume of ammonia obtained starting from 2 L of nitrogen, if the conversion  is only `6%` efficient in the given conditions? 

Explanation

Conversion of nitrogen to ammonia is given as `N_(2)+3H_(2)to 2NH_(3)`
1 mole of `N_(2)` =2 moles of `NH_(3)`
1 volume of `N_(2)=2` volumes of `NH_(3)`
Volume of ammonia with 100% efficient conversion of 2L nitrogen =4L
Volume of ammonia with 6% efficient conversion of the reaction `=(6 xx 4)/(100)=0.24L`