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11.2 L of oxygen STP and 8 grams of calc...

11.2 L of oxygen STP and 8 grams of calcium are allowed to react. What volume of which chemical 3 is left unreacted? 

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The balanced chemical equation is
`2Ca+O_(2)to 2CaO`
2 moles of Ca=1 moles of `O_(2)`
(2 x 40) grams of Ca=22.4 L of `O_(2)` at STP
8 grams of Ca=2.24 L of `O_(2)` at STP
The limiting reagent is calcium.
Volume of `O_(2)` at STP required=2.24 L
Volume of `O_(2)` left unreacted =11.2-2.24
=8.96 L at STP
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