Home
Class 11
CHEMISTRY
The energy of an electromagnetic radiati...

The energy of an electromagnetic radiation is `19.875 xx 10^(-13)` ergs. What is the wave number in `cm^(-1)` ? (`h = 6.625 xx 10^(-27)` erg.sec, `c = 3 xx 10^(10) cm.sec^(-1)`)

Text Solution

Verified by Experts

The correct Answer is:
`10,000 cm^(-1)`
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    AAKASH SERIES|Exercise Level-II (Type - II) (Practice sheet-1 (subjective/Analytical type Questions))|8 Videos

  • ATOMIC STRUCTURE

    AAKASH SERIES|Exercise Level-II (Type - II) (Lecture sheet-2 (subjective/Analytical type Questions))|8 Videos

  • ATOMIC STRUCTURE

    AAKASH SERIES|Exercise Level - II (Type-I) (Practice sheet - 6 (Section -C : Matching/Straight objective type questions))|2 Videos

  • AROMATIC HYDROCARBONS

    AAKASH SERIES|Exercise OBJECTIVE EXERCIES - 3 (RECENT AIPMT/NEET QUESTIONS)|10 Videos

  • CHEMICAL BONDING

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE -3 (RECENT AIPMT/NEET QUESTIONS )|39 Videos

Similar Questions

Explore conceptually related problems

The energy of an electromagnetic radiation is 19.875 xx 10^(-13)erg . What is its wave number in cm^(-1) ? (h=6.625xx10^(-27)erg-s, c=3xx10^(10)cms^(-1))

The energy of an electromagnetic radiation is 3 xx 10^(-12) ergs. What is its wavelength in nanometers ? ( h = 6.625 xx 10^(-27) erg.sec, C = 3 xx 10^(10) cm.sec^(-1)

The energy of a photon is 3 xx10^(-12)erg .What is its wavelength in nm? (h=6.62xx10^(-27)erg-s,3xx10^(10)cm s^(-1))

If the kinetic energy of an electron is 4.55 xx 10^(-25)J , find its wavelength (Planck's cosntant, h = 6.625 xx 10^(-34) kgm^(2)s^(-1), m = 9.1 xx 10^(-31)kg ).

The uncertainty in the position and velocity of a particle are 10^(-10)m and 5.25 xx 10^(-24) ms^(-1) . What is the mass of the particle ? (h = 6.625 xx 10^(-34) Js)