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Specific rotation for alpha-anomer of a ...

Specific rotation for `alpha`-anomer of a given mono saccharide is `100^(@)` and for `beta`-anomer is `+20^(@)`, specific rotation of equilibrium mixture is `68^(@)`, if % of `alpha` anomer is `x xx 10%` then 'x' is

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The correct Answer is:
6
Percentage of `alpha` = 10x%, Percentage of ` beta`- anomer = (100-10x)%
`:. ((100 xx 10x) + (20 xx (100 - 10x)))/(100) = 68, x=6`
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