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An optically active compound A gave an [...

An optically active compound A gave an `[alpha]_(0)^(25) = 30^(@)` while a mixture of A and its enantiomer B, gave `[alpha]_(0)^(25) = +15^(@)`. The ratio of A to B in the mixture is

A

1 to 3

B

3 to 1

C

1 to 2

D

2 to 1

Text Solution

Verified by Experts

The correct Answer is:
B
Let then % of A= x
Then % of B= `100-x`
`:. ( [x xx 30] + [(100-x)](-30 ))/(100) = +15, x = 75%`
`:.` % of A= 75%, of B= 25
Ratio of A to B `= (75)/(25) = (3)/(1) or 3 : 1`
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