Passage - VI :
Industrially sulphuric acid is produced by the following steps:
Stage I : `S+O_(2) overset(Delta)to SO_(2)`
Stage II : `2SO_(2) +O_(2) overset(V_(2)O_(5))to 2SO_(3)`
Stage III : `SO_(3)+H_(2)O to H_(2)SO_(4)`
Since the reaction between `SO_(3) and H_(2)O` is violent,
`SO_(3)` is passed into `98% H_(2)SO_(4)` to produce oleum `(H_(2)S_(2)O_(7))`
`H_(2)SO_(4)+PCl_(5) to (X) overset(H_(2)O)to ` two strong acids where 'x' is

Options

A. `SO_(2)Cl_(2)`
B. SOCl
C. `ClSO_(3)H`
D. `POCl_(3)`

Answer

A

Explanation

`SO_(2)Cl_(2)+2H_(2)O to 2HCl +H_(2)SO_(4)`