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In alkaline medium KMnO4 can be converte...

In alkaline medium `KMnO_4` can be converted into `MnO_3`. The decreas in oxidation sate in n so equivalent mass of `KMnO_(4) = ("Molar mass")/(n), ` what is n ?

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The correct Answer is:
3
`M^(+7) NO_(4)^(-) rarr M^(+4) nO_2`
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