Home
Class 11
PHYSICS
Pressure depends on distance as P =(alph...

Pressure depends on distance as `P =(alpha)/(beta) "exp" (-(alphaz)/(ktheta))` where `alpha beta` are constants z is distance k is Boltzmann is constant and `theta` is temperature. The dimension of `beta` are

A

`M^(0)L^(0)T^(0)`

B

`M^(-1)L^(-1)T^(-1)`

C

`M^(0)L^(2)T^(0)`

D

`M^(-1)L^(1)T^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - III)|11 Videos
  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - IV)|15 Videos
  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (PRACTICE SHEET (ADVANCED))|14 Videos
  • UNITS AND MEASUREMENT

    AAKASH SERIES|Exercise Practice Exercise|45 Videos
  • VECTORS

    AAKASH SERIES|Exercise Additional Practice Exercise (Practice Sheet (Advanced)) (Integer Type Questions)|6 Videos

Similar Questions

Explore conceptually related problems

In the equation ((1)/(Pbeta))=(y)/(K_(B)T) when P is the pressure y is the distance k_(B) is Boltzmann constant and T is the temperature . Dimensions of are

If alpha, beta are solutions of a tan theta + b sec theta = c then tan (alpha + beta)=

If tan (alpha - beta) = 7/24 and tan alpha = 4/3 , where alpha , beta are in first quadrant P.T alpha + beta = pi//2