A constant force F = m(2)g//2 is applie...

A constant force `F = m_(2)g//2` is applied on the block of mass nij as shown. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of `m_(1)`

`(m_2g)/(2m_1)`

`(m_2g)/(2(m_1+m_2))`s

`(3m_2g)/(2(m_1+m_2))`s

`(m_2g)/(2(2m_1)`s

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