Sulphuric acid reacts with sodium hydroxide as follows
`H_(2)SO_(4)+2NaOHrarrNa_(2)SO_(4)+2H_(2)O`
when 1L of 0.1M sulphuric acid solution is allowed to react with 1L of 0.1M sodium hydroxide solution, the amount of sodium solphate formed and its molarity in the solution obtained is

Options

A. `0.1"mol"L^(-1)`
B. `7.10g`
C. `0.025"mol"L^(-1)`
D. 3.55g

Explanation

To solve the problem, we need to determine the amount of sodium sulfate (Na2SO4) formed when 1L of 0.1M sulfuric acid (H2SO4) reacts with 1L of 0.1M sodium hydroxide (NaOH), and also find the molarity of the resulting solution.

### Step-by-Step Solution:

1. **Write the Balanced Chemical Equation:**
The reaction between sulfuric acid and sodium hydroxide is given by:
\[
H_2SO_4 + 2NaOH \rightarrow Na_2SO_4 + 2H_2O
...