Home
Class 11
CHEMISTRY
Assertion(A) Combustion of 16g of methan...

Assertion(A) Combustion of 16g of methane give18 g of water.
Reason(R) in the combustion of methane, water is one of the products.

A

Both A and R are true and R is the correct explnanation of A.

B

A is true but R is false.

C

A is false but R is true.

D

Both A and R are flase.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the assertion and reason question regarding the combustion of methane, we will follow these steps: ### Step 1: Write the balanced chemical equation for the combustion of methane. The combustion of methane (CH₄) can be represented by the following balanced equation: \[ \text{CH}_4 + 2 \text{O}_2 \rightarrow \text{CO}_2 + 2 \text{H}_2\text{O} \] ### Step 2: Identify the mass of methane and the expected mass of water produced. According to the question, the assertion states that the combustion of 16 grams of methane produces 18 grams of water. ### Step 3: Calculate the molar mass of methane (CH₄). To find the molar mass of methane: - Carbon (C) has an atomic mass of 12 g/mol. - Hydrogen (H) has an atomic mass of 1 g/mol, and there are 4 hydrogen atoms in methane. Calculating the molar mass: \[ \text{Molar mass of CH}_4 = 12 + (4 \times 1) = 12 + 4 = 16 \text{ g/mol} \] ### Step 4: Calculate the molar mass of water (H₂O). To find the molar mass of water: - Hydrogen (H) has an atomic mass of 1 g/mol, and there are 2 hydrogen atoms in water. - Oxygen (O) has an atomic mass of 16 g/mol. Calculating the molar mass: \[ \text{Molar mass of H}_2\text{O} = (2 \times 1) + 16 = 2 + 16 = 18 \text{ g/mol} \] ### Step 5: Determine the amount of water produced from the combustion of methane. From the balanced equation, 1 mole of methane produces 2 moles of water. Therefore, if 16 grams (1 mole) of methane is combusted, it will produce: \[ 2 \text{ moles of H}_2\text{O} = 2 \times 18 \text{ g/mol} = 36 \text{ grams of water} \] ### Step 6: Compare the calculated mass of water with the assertion. The assertion states that 16 grams of methane produces 18 grams of water, which is incorrect. The actual amount of water produced is 36 grams. ### Step 7: Evaluate the reason. The reason states that water is one of the products of the combustion of methane, which is true as per the balanced equation. ### Conclusion: - The assertion (A) is **false** because 16 grams of methane produces 36 grams of water, not 18 grams. - The reason (R) is **true** because water is indeed a product of the combustion of methane. Thus, the correct answer is that the assertion is false, and the reason is true. ---

To solve the assertion and reason question regarding the combustion of methane, we will follow these steps: ### Step 1: Write the balanced chemical equation for the combustion of methane. The combustion of methane (CH₄) can be represented by the following balanced equation: \[ \text{CH}_4 + 2 \text{O}_2 \rightarrow \text{CO}_2 + 2 \text{H}_2\text{O} \] ### Step 2: Identify the mass of methane and the expected mass of water produced. ...
Promotional Banner

Topper's Solved these Questions

  • REDOX REACTIONS

    NCERT EXEMPLAR ENGLISH|Exercise LONG ANSWER TYPE QUESTIONS|6 Videos
  • STATES OF MATTER

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer Type Question|6 Videos

Similar Questions

Explore conceptually related problems

18 g of water contain:

18g of water contains

Write the combustion reactions of methane

The amont of water produced by the combustion of 16 g of methane is

The number of molecules in 16g of methane is:

In the combustion of 2.0 g of methane 25 kcal heat is liberated, heat of combustion of methane would be ___________ .

Calculate the amount of water (g) produced by the combustion of 16 g of methane

Assertion (A). Combustion of all organic compounds is an exothermic reaction. Reason (R). The enthalpies of all elements in their standard state are zero

Assertion :- For the combustion of methane DeltaHltDeltaU at 125^(@)C Reason :- For combustion DeltaH is always less than DeltaU

The number of moles of methane in 320 g is

NCERT EXEMPLAR ENGLISH-SOME BASIC CONCEPTS OF CHEMISTRY-All Questions
  1. Distinguish between molarity and molality.

    Text Solution

    |

  2. Calculate the mass per cent of calcium, phosphorus and oxygen in calci...

    Text Solution

    |

  3. 45.4L of dinitrogen reacted with 22.7L of dioxygen and 45.4 L of nitro...

    Text Solution

    |

  4. If two elements can combine to form more than one compound, the masses...

    Text Solution

    |

  5. Calculate the average atomic mass of hydrogen using the following data...

    Text Solution

    |

  6. Hydrogen gas is prepared in the laboratory by reacting dilute HCl with...

    Text Solution

    |

  7. The density of 3 molal solution of NaOH is 1.110g mL^(-1). Calculate t...

    Text Solution

    |

  8. Volume of a solution chagnes with chagne in temperature, then what wil...

    Text Solution

    |

  9. If 4 g of NaOH dissovles in 36g of H(2)O, calculate the mole fraction ...

    Text Solution

    |

  10. The reactant which is entirely consumed in reaction is known as limiti...

    Text Solution

    |

  11. Match the following.

    Text Solution

    |

  12. Match the following physical quantities with units.

    Text Solution

    |

  13. Assertion(A) The empirical mass of ethene is half of its molecular mas...

    Text Solution

    |

  14. Assertion(A) One atomic mass unit is defined as one twelth of the mass...

    Text Solution

    |

  15. Assertion(A) Significant figures for 0.200 is 3 where as for 200 it is...

    Text Solution

    |

  16. Assertion(A) Combustion of 16g of methane give18 g of water. Reason(...

    Text Solution

    |

  17. A vessel contains 1.6g of dioxygen at STP(273.15k,1atm pressure). The ...

    Text Solution

    |

  18. Calcium carbonate reacts with aqueous HCl to give CaCl(2) and CO(2) a...

    Text Solution

    |

  19. Define the law of multiple proportions, Explain it with examples. How ...

    Text Solution

    |

  20. A box contains some identical red coloured balls. Labelled as A, each ...

    Text Solution

    |