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A wire is suspended from the ceiling and...

A wire is suspended from the ceiling and stretched under the action of weight F suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight.

A

Tensile stress at any cross-section A of the wire is F/A

B

Tensile stress at any cross-section is zero

C

Tensile stress at any cross-section A of the wire is 2F/A

D

Tensile at any cross-section A of the wire is F

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The correct Answer is:
To solve the problem, we need to analyze the situation of a wire suspended from the ceiling with a weight \( F \) acting on it. We will determine the tensile force and tensile stress in the wire. ### Step-by-Step Solution: 1. **Understanding the Setup**: - A wire is suspended vertically from the ceiling. - A weight \( F \) is attached to the free end of the wire. - The wire experiences tension due to the weight. **Hint**: Visualize the scenario with a diagram showing the wire, ceiling, and weight. 2. **Identifying Forces**: - The weight \( F \) exerts a downward force on the wire. - The ceiling exerts an upward force (tension \( T \)) on the wire. - Since the wire is in equilibrium, the tension in the wire must equal the weight: \[ T = F \] **Hint**: Remember that in equilibrium, the sum of forces acting on the wire must be zero. 3. **Defining Tensile Force**: - The tensile force in the wire is the force that causes elongation. - In this case, the tensile force \( T \) is equal to the weight \( F \): \[ \text{Tensile Force} = T = F \] **Hint**: Recognize that the tensile force is the same throughout the wire since it is massless. 4. **Calculating Tensile Stress**: - Tensile stress is defined as the tensile force per unit area of cross-section: \[ \text{Tensile Stress} = \frac{\text{Tensile Force}}{\text{Area}} = \frac{F}{A} \] - Here, \( A \) is the cross-sectional area of the wire. **Hint**: Recall the formula for stress, which is force divided by area. 5. **Conclusion**: - The tensile force in the wire is \( F \). - The tensile stress at any cross-section of the wire is \( \frac{F}{A} \). ### Final Answers: - **Tensile Force**: \( F \) - **Tensile Stress**: \( \frac{F}{A} \)

To solve the problem, we need to analyze the situation of a wire suspended from the ceiling with a weight \( F \) acting on it. We will determine the tensile force and tensile stress in the wire. ### Step-by-Step Solution: 1. **Understanding the Setup**: - A wire is suspended vertically from the ceiling. - A weight \( F \) is attached to the free end of the wire. - The wire experiences tension due to the weight. ...
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