A steel wire of mass `mu` per unit length with a circular cross-section has a radius of `0.1cm`. The wire is of length `10m` when measured lying horizontal, and hangs from a hook on the wall. A mass fo `25kg` is hung from the free end of the wire. Assume the wire to be uniform and laterla strain `lt lt` logitudinal strain. If density of steel is `7860 kg m^(-3)` and Young's modulus is `2xx10^(11) N//m^(2)` then the extension in the length fo the wire is

Explanation

To solve the problem of finding the extension in the length of the steel wire, we will break it down into steps.

### Step 1: Calculate the mass of the wire
The mass per unit length of the wire is denoted as \( \mu \). We can calculate the mass of the wire using its density and volume.

1. **Calculate the volume of the wire**:
\[
V = \text{Cross-sectional area} \times \text{Length}
...