Amphoteric hydroxides react with both alkalies and acids. Which of the following Group 2 metal hydroxides is soluble in sodium hydroxide?

Options

A. `Be(OH)_(2)`
B. `Mg(OH)_(2)`
C. `Ca(OH)_(2)`
D. `Ba(OH)_(2)`

Explanation

To solve the question regarding which Group 2 metal hydroxide is soluble in sodium hydroxide, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Amphoteric Hydroxides**:
Amphoteric hydroxides can react with both acids and bases. This means they can exhibit both acidic and basic properties.

2. **Identify the Group 2 Metal Hydroxides**:
The Group 2 metal hydroxides include:
- Magnesium hydroxide (Mg(OH)₂)
- Calcium hydroxide (Ca(OH)₂)
- Strontium hydroxide (Sr(OH)₂)
- Barium hydroxide (Ba(OH)₂)
- Beryllium hydroxide (Be(OH)₂)

3. **Determine Solubility in Sodium Hydroxide**:
Sodium hydroxide (NaOH) is a strong base. Generally, a hydroxide that is amphoteric can react with another base. Among the Group 2 hydroxides, beryllium hydroxide (Be(OH)₂) is known to be amphoteric and can react with strong bases like NaOH.

4. **Reactions of Beryllium Hydroxide**:
When beryllium hydroxide reacts with sodium hydroxide, it forms a soluble complex:
\[ \text{Be(OH)}_2 + 2 \text{NaOH} \rightarrow \text{Na}_2\text{Be(OH)}_4 \]
This indicates that beryllium hydroxide is soluble in sodium hydroxide.

5. **Conclusion**:
Therefore, the Group 2 metal hydroxide that is soluble in sodium hydroxide is **Beryllium hydroxide (Be(OH)₂)**.

### Final Answer:
**Beryllium hydroxide (Be(OH)₂)** is the Group 2 metal hydroxide that is soluble in sodium hydroxide.