Home
Class 11
PHYSICS
A satellite is to be placed in equatoria...

A satellite is to be placed in equatorial geostationary orbit around earth for communication.
(a) Calculate height of such a satellite.
(b) Find out the minimum number of satellites that are needed to cover entire earth so that at least one satellites is visible from any point on the equator.
`[M = 6 xx 10^(24) kg, R = 6400 km, T = 24 h, G = 6.67 xx 10^(-11) SI units]`

Text Solution

AI Generated Solution

To solve the problem step by step, let's break it down into two parts as specified in the question. ### Part (a): Calculate the height of a geostationary satellite. 1. **Given Data:** - Mass of Earth, \( M = 6 \times 10^{24} \, \text{kg} \) - Radius of Earth, \( R = 6400 \, \text{km} = 6.4 \times 10^6 \, \text{m} \) - Gravitational constant, \( G = 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \) ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    NCERT EXEMPLAR ENGLISH|Exercise Short Answer type question|6 Videos

  • KINETIC THEORY

    NCERT EXEMPLAR ENGLISH|Exercise Multiple Choice Questions (MCQs)|31 Videos

Similar Questions

Explore conceptually related problems

If the kinetic energy of a satellite orbiting around the earth is doubled then

A satellite can be in a geostationary orbit around earth in an orbit of radius r . If the angular velocity of earth about its axis doubles, a satellite can now be in a geostationary orbit aroun earth radius

A satellite can be in a geostationary orbit around earth in an orbit of radius r . If the angular velocity of earth about its axis doubles, a satellite can now be in a geostationary orbit aroun earth radius

A geostationary satellite orbits the Earth at a height of nearly 36,000 km from the surface of earth. What is the potential due to earth's gravity at the site of this satllite ? (Take the potential energy at infinity to be zero). Mass of the Earth = 6.0 xx 10^(24) kg , radius = 6400 km, G = 6.67 xx 10^(-11) Nm^(2)//kg^(2) .

For a geostationary satellite orbiting around the earth identify the necessary condition.

Calculate the height above the earth at which the geostationary satellite is orbiting the earth. Radius of earth = 6400km. Mass of earth = 6 xx 10^(24) kg. G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

A satellite is projected vertically upwards from an earth station. At what height above the earth's surface will the force on the satellite due to the earth be reduced to half its value at the earth station? (Radius of the earth is 6400 km.)

A geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of earth. What is the potential due to earth's gravity at the site of this satellite? ( Take the potential energy at infinity to be zero). Mass of the earth 6.0 xx 10^(24) kg , radius = 6400km.

The minimum number of communication satellites (Geostationary) required to link the communication network of entire earth is

If an artificial satellite is moving in a circular orbit around earth with speed equal to one fourth of V_(e) from earth, then height of the satellite above the surface of the earth is