In the extraction of Cu from its sulphide ore, the metal is formed by reduction of `Cu_(2)O` with

Options

A. FeS
B. CO
C. `Cu_(2)S`
D. `SO_(2)`

Explanation

To solve the question regarding the extraction of copper from its sulphide ore, we will follow these steps:

### Step-by-Step Solution:

1. **Understanding the Ore**:
Copper is primarily extracted from its sulphide ores, specifically from copper(I) sulphide (Cu₂S).

2. **Initial Processing**:
The copper ore is first subjected to a process where it is mixed with silica in a converter. This mixture is then heated, resulting in the formation of copper matte, which consists of Cu₂S and iron(II) sulphide (FeS).

3. **Roasting**:
The copper matte is then roasted, which converts Cu₂S into copper(I) oxide (Cu₂O). During this roasting process, iron(II) sulphide is converted into slag.

4. **Reduction Reaction**:
The next step involves the reduction of Cu₂O to form metallic copper (Cu). The reducing agent in this reaction is Cu₂S. The balanced chemical reaction for this reduction can be represented as:
\[ 2Cu_2S + 3O_2 \rightarrow 4Cu + 2SO_2 \]
Here, Cu₂S reacts with Cu₂O to produce copper and sulfur dioxide (SO₂).

5. **Final Product**:
The copper produced from this reaction is known as blister copper due to its blistered appearance caused by the evolution of sulfur dioxide gas during the reduction process.

6. **Conclusion**:
Therefore, in the extraction of copper from its sulphide ore, the metal is formed by the reduction of Cu₂O with Cu₂S.

### Final Answer:
The metal is formed by the reduction of Cu₂O with Cu₂S.

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