Home
Class 11
CHEMISTRY
Direction (Q. Nos. 19-20) Consider the f...

Direction (Q. Nos. 19-20) Consider the following four compounds
(I) `CH_(3) - CH_(2) - CH_(2) - CH_(2) - overset(O)overset(||)(C) - H`
(II) `CH_(3) - CH_(2) - CH_(2) - overset(O)overset(||)(C) - CH_(3)`
(III) `CH_(3) - CH_(2) - underset(O)underset(||)(C) - CH_(2) - CH_(3)`
(IV) `CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - underset(O)underset(||)(C) - H`
Which of the following pairs are not functional group isomers ?

A

II and III

B

II and IV

C

I and IV

D

I and II

Text Solution

AI Generated Solution

The correct Answer is:
To determine which pairs of the given compounds are not functional group isomers, we need to analyze each compound's molecular formula and functional groups. Functional group isomers have the same molecular formula but different functional groups. ### Step-by-Step Solution: 1. **Identify the Compounds and Their Structures:** - (I) `CH3 - CH2 - CH2 - CH2 - C(=O) - H` (Aldehyde) - (II) `CH3 - CH2 - CH2 - C(=O) - CH3` (Ketone) - (III) `CH3 - CH2 - C(=O) - CH2 - CH3` (Ketone) - (IV) `CH3 - C(CH3) - CH2 - C(=O) - H` (Aldehyde) 2. **Determine the Molecular Formula for Each Compound:** - For (I): C5H10O - For (II): C5H10O - For (III): C5H10O - For (IV): C5H10O 3. **Identify Functional Groups:** - (I) has an aldehyde functional group. - (II) has a ketone functional group. - (III) has a ketone functional group. - (IV) has an aldehyde functional group. 4. **Analyze Each Pair:** - **Pair (II) and (III):** Both have the same functional group (ketone). Therefore, they are not functional group isomers. - **Pair (II) and (IV):** Different functional groups (ketone and aldehyde). They are functional group isomers. - **Pair (I) and (IV):** Both have the same functional group (aldehyde). Therefore, they are not functional group isomers. - **Pair (I) and (II):** Different functional groups (aldehyde and ketone). They are functional group isomers. 5. **Conclusion:** - The pairs that are not functional group isomers are (II) and (III), and (I) and (IV). ### Final Answer: The pairs that are not functional group isomers are: - (II) and (III) - (I) and (IV)

To determine which pairs of the given compounds are not functional group isomers, we need to analyze each compound's molecular formula and functional groups. Functional group isomers have the same molecular formula but different functional groups. ### Step-by-Step Solution: 1. **Identify the Compounds and Their Structures:** - (I) `CH3 - CH2 - CH2 - CH2 - C(=O) - H` (Aldehyde) - (II) `CH3 - CH2 - CH2 - C(=O) - CH3` (Ketone) - (III) `CH3 - CH2 - C(=O) - CH2 - CH3` (Ketone) ...
Promotional Banner

Topper's Solved these Questions

  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    NCERT EXEMPLAR ENGLISH|Exercise Short Answer type question|27 Videos
  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    NCERT EXEMPLAR ENGLISH|Exercise Matching the columns|5 Videos
  • HYDROGEN

    NCERT EXEMPLAR ENGLISH|Exercise LONG ANSWER TYPE QUESTIONS|8 Videos
  • REDOX REACTIONS

    NCERT EXEMPLAR ENGLISH|Exercise LONG ANSWER TYPE QUESTIONS|6 Videos

Similar Questions

Explore conceptually related problems

Direction (Q. Nos. 19-20) Consider the following four compounds (I) CH_(3) - CH_(2) - CH_(2) - CH_(2) - overset(O)overset(||)(C) - H (II) CH_(3) - CH_(2) - CH_(2) - overset(O)overset(||)(C) - CH_(3) (III) CH_(3) - CH_(2) - underset(O)underset(||)(C) - CH_(2) - CH_(3) (IV) CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - underset(O)underset(||)(C) - H Which of the following pairs are position isomers ?

CH_(3)-CH_(2)-CH_(2)-underset(OH)underset(|)(C )H-CH_(3) and CH_(3)-CH_(2)-underset(OH)underset(|)(C )H-CH_(2)-CH_(2)-CH_(3) are

Among these chain isomers are : (I) CH_(3)-CH_(3)-CH_(2)-CH_(2)-OH (II) CH_(3)-CH_(2)-underset(OH)underset(|)(CH)-CH_(3) (III) CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)(C)-CH_(3)

Which of the following is the correct ease of dehydration ? I CH_(3) - CH_(2)-CH_(2)-underset(OH)underset(|)(CH_(2)) , II CH_(3)-CH_(2)-overset(OH)overset(|)(CH)-CH_(3) , III CH_(2) = CH -overset(OH)overset(|)(CH)-CH_(3) , IV

Write the IUPAC names of the following compounds (i) CH_(3)-CH_(2)-overset(O)overset(||)(C)-CH_(2)-overset(O)overset(||)(C)-CH_(3) (ii) CH_(3)-overset(O)overset(||)(C)-CH_(2)-CH_(2)-CH_(2)-CH_(2)-COOH (iii) CH_(3)-underset(C_(2)H_(5))underset(|)(CH)-underset(C_(2)H_(5))underset(|)(CH)-CH_(3)

CH_(3)-underset(Cl)underset(|)(C )H-underset(I)underset(|)(C )H-CH_(3) CH_(3)-underset(CH_(3))underset(|)(C)H-(CH_(2))_(4)-underset(CH_(3))underset(|)(C )H-underset(Br)underset(|)(C )H-CH_(2)CH_(3)

I. CH_(3) - CH_(2) - CH_(2) - CH_(2) - OH II. CH_(3) - CH_(2) - underset(OH)underset(|)(CH) - CH_(3) III. CH_(3) - underset(OH) underset(|)overset(CH_(3))overset(|)(C) - CH_(3) IV. CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - OH V. CH_(3) - CH_(2) - O - CH_(2) - CH_(3) VI. CH_(3) - O - CH_(2) - CH_(2) - CH_(3) VII. CH_(3) - O - underset(CH_(3))underset(|)(CH) - CH_(3) Which of the above compounds form pairs of metamers ?