Standard molar enthalpy of formation, `Delta_(f) H^(Θ)` is just a special case of enthalpy of reaction, `Delta_(r) H^(Θ)`. Is the `Delta_(r) H^(Θ)` same as standard molar enthalpy of formation ? Given reason for your answer.
`CaO (s) + CO_(2) (g) rarr CaCO_(3) (s) , Delta_(f) H^(Θ) = - 178.3 kJ mol^(-1)`

Explanation

To determine whether the standard molar enthalpy of formation, \( \Delta_f H^\Theta \), is the same as the standard enthalpy of reaction, \( \Delta_r H^\Theta \), we will analyze the given reaction and the definitions of these terms.

### Step 1: Understand the Definitions
- **Standard Enthalpy of Formation (\( \Delta_f H^\Theta \))**: This is the enthalpy change when one mole of a compound is formed from its elements in their most stable states at standard conditions (1 bar pressure and a specified temperature, usually 25°C).
- **Standard Enthalpy of Reaction (\( \Delta_r H^\Theta \))**: This is the enthalpy change for a given reaction under standard conditions.

### Step 2: Analyze the Given Reaction
The reaction provided is:
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