The enthalpy of reaction for the reaction
`2H_(2) (g) + O_(2) (g) rarr 2H_(2) O (l) " is " Delta_(r) H^(Θ) = - 572 kJ mol^(-1)`
What will be standard enthalpy of formation of `H_(2) O (l)` ?

Explanation

To find the standard enthalpy of formation of \( H_2O (l) \) from the given reaction:

**Step 1: Understand the Reaction**
The reaction given is:
\[ 2H_2 (g) + O_2 (g) \rightarrow 2H_2O (l) \]
The enthalpy change for this reaction is given as:
\[ \Delta_r H^{\Theta} = -572 \, \text{kJ/mol} \]

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