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In the F(2) generation a Mendelian dihyb...

In the `F_(2)` generation a Mendelian dihybrid cross the number of phenotypes and genotypes are

A

phenotypes-4 genotypes-16

B

phenotypes-9, genotypes-4

C

phenotypes-4, genotypes-8

D

phenotypes-4, genotypes-9

Text Solution

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The correct Answer is:
To solve the question regarding the number of phenotypes and genotypes in the F2 generation of a Mendelian dihybrid cross, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Dihybrid Cross**: A dihybrid cross involves two traits, each represented by two alleles. For example, consider traits for seed shape (round vs. wrinkled) and seed color (yellow vs. green). 2. **Identify Parental Generation (P)**: Let's assume we are crossing two true-breeding plants: one with round yellow seeds (RRYY) and another with wrinkled green seeds (rryy). 3. **Determine F1 Generation**: The F1 generation will all be heterozygous for both traits (RrYy), showing the dominant phenotypes (round yellow seeds). 4. **Perform F1 Self-Cross**: To find the F2 generation, we cross two F1 individuals (RrYy x RrYy). 5. **Use Punnett Square**: Create a 4x4 Punnett square to determine the genotypes of the F2 generation. Each parent can produce four types of gametes: RY, Ry, rY, and ry. 6. **Count Genotypes**: After filling in the Punnett square, we find the following genotypic ratios: - 1 RRYY (homozygous round yellow) - 2 RrYY (heterozygous round yellow) - 1 rrYY (homozygous round yellow) - 2 RRYy (homozygous round yellow) - 4 RrYy (heterozygous round yellow) - 2 Rryy (heterozygous wrinkled yellow) - 1 rryy (homozygous wrinkled green) This gives us a total of 9 different genotypes. 7. **Count Phenotypes**: The phenotypes resulting from the F2 generation can be summarized as: - Round Yellow (R_Y): 9 - Round Green (R_yy): 3 - Wrinkled Yellow (rrY_): 3 - Wrinkled Green (rryy): 1 This results in a total of 4 distinct phenotypes. 8. **Conclusion**: Therefore, in the F2 generation of a Mendelian dihybrid cross, the number of phenotypes is 4, and the number of genotypes is 9. ### Final Answer: - **Phenotypes**: 4 - **Genotypes**: 9 ---

To solve the question regarding the number of phenotypes and genotypes in the F2 generation of a Mendelian dihybrid cross, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Dihybrid Cross**: A dihybrid cross involves two traits, each represented by two alleles. For example, consider traits for seed shape (round vs. wrinkled) and seed color (yellow vs. green). 2. **Identify Parental Generation (P)**: ...
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