Which product is formed when the compound is treated with concentrated aqueous KOH solution ?

Options

A.
B.
C.
D.

Explanation

To determine the product formed when benzaldehyde is treated with concentrated aqueous KOH solution, we will follow these steps:

### Step 1: Identify the Reactant
The reactant in this case is benzaldehyde, which has the structure C6H5CHO. It is an aromatic aldehyde.

### Step 2: Understand the Reaction Conditions
The reaction involves concentrated aqueous KOH, which is a strong base. In the presence of a strong base, aldehydes can undergo reactions such as the Cannizzaro reaction, especially when they lack alpha-hydrogens.

### Step 3: Check for Alpha-Hydrogens
Benzaldehyde does not have any alpha-hydrogens (hydrogens attached to the carbon adjacent to the carbonyl carbon). This is crucial because the absence of alpha-hydrogens means that it cannot undergo aldol condensation but can undergo the Cannizzaro reaction.

### Step 4: Cannizzaro Reaction
In the Cannizzaro reaction, one molecule of benzaldehyde is oxidized to benzoic acid (C6H5COOH), while another molecule is reduced to benzyl alcohol (C6H5CH2OH).

### Step 5: Write the Reaction Products
1. **Oxidation Product**: Benzoic acid (C6H5COOH)
2. **Reduction Product**: Benzyl alcohol (C6H5CH2OH)

### Step 6: Conclusion
Thus, when benzaldehyde is treated with concentrated aqueous KOH, the products formed are benzoic acid and benzyl alcohol.

### Final Answer
The products formed are benzoic acid and benzyl alcohol.

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