Treatement of compound `Ph-O-overset(O)overset(||)(C)-Ph`
with NaOH solution yields

Options

A. phenol
B. sodium phenoxide
C. sodium benzoate
D. benzophenone

Explanation

To solve the question regarding the treatment of the compound `Ph-O-C(=O)-Ph` (where `Ph` represents the phenyl group) with NaOH solution, we can follow these steps:

### Step 1: Identify the Structure
The compound `Ph-O-C(=O)-Ph` can be recognized as a phenyl ether with a carbonyl group (specifically, it is a phenyl ester). The structure can be represented as:
- Ph-O- (phenyl group connected to an oxygen)
- C(=O)- (carbonyl group)
- Ph (another phenyl group)

### Step 2: Understand the Reaction with NaOH
When this compound is treated with sodium hydroxide (NaOH), the hydroxide ion (OH⁻) acts as a nucleophile. The carbonyl carbon is electrophilic and will be attacked by the hydroxide ion.

### Step 3: Nucleophilic Attack
The hydroxide ion will attack the carbonyl carbon (C=O) of the ester. This leads to the breaking of the C-O bond, resulting in the formation of a phenoxide ion and a carboxylate ion.

### Step 4: Formation of Products
1. The phenoxide ion is formed from the phenyl group attached to the oxygen. This can be represented as:
- Ph-O⁻ (sodium phenoxide when combined with Na⁺ from NaOH)
2. The other product formed is a carboxylate ion, which can be represented as:
- Ph-C(=O)O⁻ (sodium benzoate when combined with Na⁺ from NaOH)

### Step 5: Final Products
Thus, the final products of the reaction are:
- Sodium phenoxide (Ph-O⁻Na⁺)
- Sodium benzoate (Ph-C(=O)O⁻Na⁺)

### Conclusion
The treatment of the compound `Ph-O-C(=O)-Ph` with NaOH solution yields sodium phenoxide and sodium benzoate.