Ethylene cghloride and ethylidene chloride are isomers. Identify the correct statements.

Options

A. Both the compounds form same product on treatment wih alcoholic KOH
B. Both the compounds form same product on treatment with aq. NaOH
C. Both the compounds form same product on reduction
D. Both the compounds are optically active

Explanation

To solve the question regarding the isomers ethylene chloride and ethylidene chloride, we will analyze the statements provided and determine which ones are correct based on their chemical behavior.

### Step-by-Step Solution:

1. **Identify the Structures of the Compounds:**
- **Ethylene Chloride (1,2-Dichloroethane)**: This compound has the structure CH2Cl-CH2Cl, where both chlorine atoms are attached to adjacent carbon atoms.
- **Ethylidene Chloride (1,1-Dichloroethane)**: This compound has the structure CH3-CCl2, where both chlorine atoms are attached to the same carbon atom.

2. **Analyze Statement A:**
- **Statement A**: Both compounds form the same product on treatment with alcoholic KOH.
- **Reaction**: Both compounds undergo dehydrohalogenation with alcoholic KOH, resulting in the formation of ethyne (C2H2) by the elimination of HCl.
- **Conclusion**: This statement is **correct**.

3. **Analyze Statement B:**
- **Statement B**: Both compounds form the same product on treatment with aqueous NaOH.
- **Reaction**:
- Ethylene chloride reacts with aqueous NaOH to form ethylene glycol (HO-CH2-CH2-OH).
- Ethylidene chloride reacts with aqueous NaOH to form ethanol (CH3-CH2-OH).
- **Conclusion**: This statement is **incorrect** because the products are different.

4. **Analyze Statement C:**
- **Statement C**: Both compounds form the same product on reduction.
- **Reaction**: Reducing both compounds will replace Cl atoms with H atoms, leading to the formation of ethane (C2H6).
- **Conclusion**: This statement is **correct**.

5. **Analyze Statement D:**
- **Statement D**: Both compounds are optically active.
- **Chirality Check**:
- Ethylene chloride has no chiral centers (two Cl atoms on adjacent carbons).
- Ethylidene chloride also lacks a chiral center (two Cl atoms on the same carbon).
- **Conclusion**: This statement is **incorrect** as both compounds are optically inactive.

### Final Conclusion:
The correct statements are:
- **A**: Both compounds form the same product on treatment with alcoholic KOH.
- **C**: Both compounds form the same product on reduction.