Methylamine reacts with `HNO_(2)` to form….

Options

A. `CH_(3)-O-N=O`
B. `CH_(3)-O-CH_(3)`
C. `CH_(3)OH`
D. `CH_(3)CHO`

Explanation

To solve the question of what methylamine reacts with HNO₂ to form, we can break it down into a series of steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are methylamine (CH₃NH₂) and nitrous acid (HNO₂).

2. **Reaction Mechanism**:
- Methylamine reacts with nitrous acid to form a diazonium salt. The reaction can be represented as follows:
\[ CH₃NH₂ + HNO₂ \rightarrow CH₃N₂^+ + H₂O \]
- In this step, the amine group (-NH₂) of methylamine is converted into a diazonium ion (CH₃N₂⁺) while releasing water.

3. **Formation of Alcohol**:
- The diazonium salt is unstable and can decompose to form nitrogen gas (N₂) and an alcohol. The nitrogen gas is a good leaving group, which means it will leave the molecule easily.
- The reaction can be summarized as:
\[ CH₃N₂^+ \rightarrow CH₃OH + N₂ \]
- Here, the diazonium salt decomposes to form methanol (CH₃OH) and nitrogen gas.

4. **Final Products**:
- The final products of the reaction between methylamine and nitrous acid are methanol (CH₃OH) and nitrogen gas (N₂). Additionally, hydrochloric acid (HCl) may be formed as a byproduct, but the main focus is on the alcohol produced.

### Conclusion:
When methylamine reacts with HNO₂, the main product formed is methanol (CH₃OH).

### Final Answer:
The product formed when methylamine reacts with HNO₂ is **methanol (CH₃OH)**.

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