Reduction of aromatic nitro compounds using Fe and HCl gives…

Options

A. aromatic oxime
B. aromatic hydrocarbon
C. aromatic primary amine
D. aromatic amide

Explanation

To solve the question regarding the reduction of aromatic nitro compounds using Fe and HCl, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are aromatic nitro compounds, which contain the nitro group (-NO2) attached to an aromatic ring.

2. **Understand the Reduction Process**:
The reduction of nitro compounds involves converting the nitro group (-NO2) into an amine group (-NH2). This process typically requires reducing agents.

3. **Identify the Reducing Agents**:
In this case, we are using iron (Fe) and hydrochloric acid (HCl) as the reducing agents. Iron serves to donate electrons, while HCl provides protons (H+) necessary for the reduction.

4. **Write the Reaction**:
When an aromatic nitro compound (R-NO2) is treated with Fe and HCl, the reaction can be summarized as:
\[ R-NO2 + 3Fe + 6HCl \rightarrow R-NH2 + 3FeCl2 + 2H2O \]
Here, R represents the aromatic ring.

5. **Identify the Product**:
The product of this reaction is an aromatic primary amine (R-NH2). This is because the nitrogen in the amine is bonded to only one carbon atom of the aromatic ring.

6. **Classify the Product**:
The product is classified as an aromatic primary amine since it contains an amine group attached to an aromatic ring and the nitrogen is connected to only one carbon atom.

### Final Answer:
The reduction of aromatic nitro compounds using Fe and HCl gives **aromatic primary amine**.

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