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A compound Z with molecular formula C(3)...

A compound Z with molecular formula `C_(3)H_(9)N` reacts with `C_(6)H_(5)SO_(2)Cl` to give a solid, insoluble in alkali. Identify Z.

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`Z(C_(3)H_(9)N)` is an aliphatic amine. On reaction with `C_(6)H_(5)SO_(2)Cl` (Hinsberg's reagent), It gives a product insolude in alkali. It means that the product does not have a replaceable H-atom attached to the N-atom. So, compound Z is a secondary amine(ethyl methyl amine).
`CH_(3)-undersetundersetundersetunderset([Z=C_(3)H_(g)N])("Ethymethylamine")(C_(2)H_(5))("| ")"NH"+C_(6)H_(5)SO_(2)Clrarrundersetundersetunderset("(Insolubie in alkali)")("benzene sulphonamide")("N-ethyl-N-methyl")(CH_(3)-N-SO_(2)C_(6)H_(5)`
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NCERT EXEMPLAR ENGLISH-AMINES-SATQ
  1. What is the structure and IUPAC name of the compound, allyl amine?

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  2. Write down the IUPAC name of

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  3. A compound Z with molecular formula C(3)H(9)N reacts with C(6)H(5)SO(2...

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  4. A primary amine, RNH(2) can be reacted with CH(3)-X to get secondary a...

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  5. Complete the following reaction

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  6. Why is aniline soluble in aqueous HCl?

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  7. Suggest a route by which of the following conversion can be accomplish...

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  8. Identfy A and B in the following reactions.

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  9. How will you carry out the follwing conversion? (i) Toluene -p-tolui...

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  10. Write following conversions (i) Nitrobenzene-Acetanilide (ii) Acet...

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  11. A solution contains 1g mol. Each of p-toluene diazonium chloride and p...

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  12. How will you bring out the following conversion?

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  13. How will you carry out the following conversion?

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  14. How will you carry out the following conversion?

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  15. How will you carry out the following conversion?

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  16. Match the reactions given in Column I with the statements given in Col...

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  17. Match the reactions given in Column I with the statements given in Col...

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  18. Assertion(A) Acylation of amines gives a monsubstituted product where...

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  19. Assertion (A): Hofmann's bromamide reaction is given by primary amines...

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  20. Assertion (A): N-ethylbenzene sulphonamide is solube in alkali. Reas...

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