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In a town of 10000 families, it was foun...

In a town of 10000 families, it was found that 40% families buy newspaper A, 20% families buy newspaper B, 10 % families buy newspaper C, 5% families buy A and B, 3% buy B and C and 4 % buy a and C. If 2% families buy all the three newspaper. Find
(i) the number of families which buy newspaper A only.
(ii) the number of families which buy none of A , B and C.

Text Solution

AI Generated Solution

To solve the problem step by step, we will use the information provided about the families in the town and the percentages of families buying each newspaper. ### Given Data: - Total families = 10,000 - Families buying newspaper A (N_A) = 40% of 10,000 = 4,000 - Families buying newspaper B (N_B) = 20% of 10,000 = 2,000 - Families buying newspaper C (N_C) = 10% of 10,000 = 1,000 - Families buying both A and B (N_A ∩ N_B) = 5% of 10,000 = 500 ...
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