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Let R be set of points inside a rectangl...

Let `R` be set of points inside a rectangle of sides `a` and `b` `(a, b > 1)` with two sides along the positive direction of x-axis and y-axis(a) `R = {(x, y) : 0 le x le a, 0 le y le b}`(b) `R = {(x,y) : 0 le x lt a, 0 le y le b}`(c) `R = {(x,y): 0 le x le a, 0 lt y lt b}`(d) `R = {(x,y): 0 lt x lt a, 0 lt y lt b}`

A

`R = {(x, y) : 0 le x le a, 0 le y le b}`

B

`R = {(x,y) : 0 le x lt a, 0 le y le b}`

C

`R = {(x,y): 0 le x le a, 0 lt y lt b}`

D

`R = {(x,y): 0 lt x lt a, 0 lt y lt b}`

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the set of points inside a rectangle defined by the sides \( a \) and \( b \) in the first quadrant of the Cartesian plane. The rectangle has its sides along the positive x-axis and y-axis. ### Step-by-step Solution: 1. **Understanding the Rectangle**: The rectangle is defined by the points (0, 0) at the origin, (a, 0) on the x-axis, (0, b) on the y-axis, and (a, b) at the opposite corner. The rectangle lies entirely in the first quadrant since both \( a \) and \( b \) are greater than 1. 2. **Defining the Set of Points**: The set \( R \) consists of all points \( (x, y) \) that lie within this rectangle. We need to determine the conditions for \( x \) and \( y \) based on the boundaries of the rectangle. 3. **Conditions for \( x \)**: - Since the rectangle extends from 0 to \( a \) along the x-axis, the possible values for \( x \) must satisfy: \[ 0 \leq x \leq a \] - However, since we are looking for points **inside** the rectangle, \( x \) cannot equal \( a \). Thus, we have: \[ 0 \leq x < a \] 4. **Conditions for \( y \)**: - Similarly, for the y-coordinate, the rectangle extends from 0 to \( b \) along the y-axis. The possible values for \( y \) must satisfy: \[ 0 \leq y \leq b \] - Again, since we are looking for points **inside** the rectangle, \( y \) cannot equal \( b \). Thus, we have: \[ 0 \leq y < b \] 5. **Combining the Conditions**: - Combining the conditions for both \( x \) and \( y \), we can express the set \( R \) as: \[ R = \{(x, y) : 0 < x < a, \, 0 < y < b\} \] 6. **Identifying the Correct Option**: - Now, we can compare our derived set with the given options: - (a) \( R = \{(x, y) : 0 \leq x \leq a, \, 0 \leq y \leq b\} \) - includes the boundaries, not correct. - (b) \( R = \{(x, y) : 0 \leq x < a, \, 0 \leq y \leq b\} \) - includes the boundary for \( y \), not correct. - (c) \( R = \{(x, y) : 0 \leq x \leq a, \, 0 < y < b\} \) - includes the boundary for \( x \), not correct. - (d) \( R = \{(x, y) : 0 < x < a, \, 0 < y < b\} \) - matches our derived set, correct. ### Conclusion: The correct option is (d) \( R = \{(x, y) : 0 < x < a, \, 0 < y < b\} \).

To solve the problem, we need to analyze the set of points inside a rectangle defined by the sides \( a \) and \( b \) in the first quadrant of the Cartesian plane. The rectangle has its sides along the positive x-axis and y-axis. ### Step-by-step Solution: 1. **Understanding the Rectangle**: The rectangle is defined by the points (0, 0) at the origin, (a, 0) on the x-axis, (0, b) on the y-axis, and (a, b) at the opposite corner. The rectangle lies entirely in the first quadrant since both \( a \) and \( b \) are greater than 1. 2. **Defining the Set of Points**: ...
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