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4/(x-1)le3le6/(x+1)(xgt0)...

`4/(x-1)le3le6/(x+1)(xgt0)`

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To solve the inequality \( \frac{4}{x-1} \leq 3 \leq \frac{6}{x+1} \) with the condition \( x > 0 \), we will break it down into two parts. ### Step 1: Solve the first part of the inequality \( \frac{4}{x-1} \leq 3 \) 1. Start by isolating the fraction: \[ \frac{4}{x-1} \leq 3 \] ...
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