Home
Class 11
MATHS
In drilling world's deepest hole it was ...

In drilling world's deepest hole it was found that the temperature T in degree Celsius, x Km below the earth's surface was given by ` T=30 + 25(x-3), 3 le x le 15`. At what depth will the temperature be between ` 155^(@)C and 205^(@)C`?

Text Solution

AI Generated Solution

To find the depth at which the temperature \( T \) is between \( 155^\circ C \) and \( 205^\circ C \), we start with the given temperature function: \[ T = 30 + 25(x - 3) \] where \( 3 \leq x \leq 15 \). ...
Promotional Banner

Topper's Solved these Questions

  • LINEAR INEQUALITIES

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer Type Question|6 Videos

  • LINEAR INEQUALITIES

    NCERT EXEMPLAR ENGLISH|Exercise Objective Type Questions|14 Videos

  • LIMITS AND DERIVATIVES

    NCERT EXEMPLAR ENGLISH|Exercise FILLERS|4 Videos

  • MATHEMATICAL REASONING

    NCERT EXEMPLAR ENGLISH|Exercise OBJECTIVE TYPE QUESTIONS|21 Videos

Similar Questions

Explore conceptually related problems

In an experiment, a solution of hydrochloric acid is to be kept between 30o and 35o Celsius. What is the range of temperature in degree Fahrenheit if conversion formula is given by C = 5/9 (F -32), where C and F represent temperature in deg

Coefficient of thermal expansion of a wire varies with temperature T as alpha = 1.6 xx 10^(-6) T , where T is temperature in degree Celsius. If the length of wire is 10 m at 0^@C , what is the change in length of wire (in mm), when its temperature is raised to 25^@C ?

A solution is to be kept between 68oF and 77oF . What is the range in temperature in degree Celsius (C) if the Celsius / Fahrenheit (F) conversion formula is given by F=9/5C+32 ?

The inequality |1.5C-24|le30 represents the range of monthly average temperature, C, in degrees Celsius, during the winter month for a certain city. What was the lowest monthly average temperature, in degrees Celsius, for for this city?

For a certain reaction the variation of rate constant with temperature is given by the equation ln k_(t) = lnk_(0) + ((ln 3)t)/(10) (t ge 0^(@)C) The value of temperature coefficient of the reaction is

For a certain reaction the variation of rate constant with temperature is given by the equation ln k_(t) = lnk_(0) + ((ln 3)t)/(10) (t ge 0^(@)C) The value of temperature coefficient of the reaction is

An air bubble starts rising from the bottom of a lake. Its diameter is 3.6 mm at the bottom and 4 mm at the surface. The depth of the lake is 250 cm and the temperature at the surface is 40^@ C . What is the temperature at the bottom of the lake? Given atmospheric pressure = 76 cm of Hg and g = 980 cm//s^2 .

Maximize Z=8x+9y , subject to the contraints given below: 2x+3y le 6, 3x-2y le 6, y le 1, x,y ge 0

Imagine a system, that can keep the room temperature within a narrow range between 20^@C to 25^@C . The system includes a heat engine operating with variable power P = 3KT, where K is a constant coefficient, depending upon the thermal insulation of the room, the area of the walls and the thickness of the walls. T is temperature of the room in temperature drops lower than 20^@C , the engine turns on, when the temperature increase over 25^@ C, the engine turns off, room looses energy at a rate of K(T - T_0), T_0 is the outdoor temperature. The heat capacity of the room is C. Given (T_0=10^@C, ln(3/2) =0.4 , ln(6/5)=0.18 , C/K =750 SI-unit) Suppose at t = 0, the engine turns off, after how much time interval, again, the engine will turn on