If the `p^(t h)a n d q^(t h)` terms of a G.P. are `q a n d p` respectively, show that `(p+q)^(t h)` term is `((q^p)/(p^q))^(1/(p-q))` .

Explanation

To solve the problem, we need to show that the (p + q)th term of a geometric progression (G.P.) is equal to \(\left(\frac{q^p}{p^q}\right)^{\frac{1}{p-q}}\), given that the pth and qth terms of the G.P. are \(q\) and \(p\) respectively.

### Step-by-Step Solution:

1. **Define the terms of the G.P.**:
Let the first term of the G.P. be \(a\) and the common ratio be \(r\). The nth term of a G.P. can be expressed as:
\[
T_n = a r^{n-1}
...