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If without repetition of the numbers, four-dight numbers are formed with the numbers 0, 2, 3 and 5, then the probability of such a number divisible by 5 is

A

`(1)/(5)`

B

`(4)/(5)`

C

`(1)/(30)`

D

`(5)/(9)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability of forming a four-digit number using the digits 0, 2, 3, and 5 that is divisible by 5, we will follow these steps: ### Step 1: Identify the total number of four-digit numbers that can be formed. Since we are forming a four-digit number, the first digit cannot be 0 (as it would not be a four-digit number). Therefore, the first digit can only be 2, 3, or 5. - **Choices for the first digit:** 3 options (2, 3, or 5) - **Choices for the second digit:** 3 options (the remaining digits including 0) - **Choices for the third digit:** 2 options (the remaining digits after choosing the first and second) - **Choices for the fourth digit:** 1 option (the last remaining digit) Calculating the total number of four-digit numbers: \[ \text{Total numbers} = 3 \times 3 \times 2 \times 1 = 18 \] ### Step 2: Determine how many of these numbers are divisible by 5. A number is divisible by 5 if its last digit is either 0 or 5. We will consider two cases based on the last digit. #### Case 1: Last digit is 0 - **Choices for the first digit:** 2 options (2 or 3 or 5) - **Choices for the second digit:** 2 options (the remaining digits excluding the first digit) - **Choices for the third digit:** 1 option (the last remaining digit) Calculating the total for this case: \[ \text{Total for last digit 0} = 2 \times 2 \times 1 = 4 \] #### Case 2: Last digit is 5 - **Choices for the first digit:** 2 options (2 or 3) - **Choices for the second digit:** 2 options (the remaining digits including 0) - **Choices for the third digit:** 1 option (the last remaining digit) Calculating the total for this case: \[ \text{Total for last digit 5} = 2 \times 2 \times 1 = 4 \] ### Step 3: Calculate the total number of four-digit numbers divisible by 5. Adding the totals from both cases: \[ \text{Total divisible by 5} = 4 + 4 = 8 \] ### Step 4: Calculate the probability. The probability \( P \) of forming a four-digit number that is divisible by 5 is given by the ratio of the number of favorable outcomes to the total outcomes: \[ P = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{8}{18} = \frac{4}{9} \] ### Final Answer: The probability of forming a four-digit number that is divisible by 5 is \( \frac{4}{9} \). ---

To solve the problem of finding the probability of forming a four-digit number using the digits 0, 2, 3, and 5 that is divisible by 5, we will follow these steps: ### Step 1: Identify the total number of four-digit numbers that can be formed. Since we are forming a four-digit number, the first digit cannot be 0 (as it would not be a four-digit number). Therefore, the first digit can only be 2, 3, or 5. - **Choices for the first digit:** 3 options (2, 3, or 5) - **Choices for the second digit:** 3 options (the remaining digits including 0) ...
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