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If M and N are any two events, then the ...

If M and N are any two events, then the probability that exactly one of them occurs is

A

`P(M)+P(N)-2P(McapN)`

B

`P(M)+P(N)-P(McapN)`

C

`P(M)+P(N)+P(McapN)`

D

`P(M)+P(N)+2P(McapN)`

Text Solution

Verified by Experts

The correct Answer is:
B
(b) If M and N are any two events.
`therefore " "P(McupN)=P(M)+P(N)-P(McupN)`
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