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If AOB is a diameter of a circle and C i...

If AOB is a diameter of a circle and C is a point on the circle, then `AC^(2)+BC^(2)=AB^(2)`.

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The correct Answer is:
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Since, any diameter of the circle subtends a right angle to any point on the circle.
If AOB is a diameter of a circle and C is a point on the circle, then `DeltaACB` is right angled atC.
In right angled `DeltaACB`, [use Pythagoras theorem]
`AC^(2)+BC^(2)=AB^(2)`
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