On a common hypotenuse AB, two right angled triangles, ACB and ADB are situated on opposite sides. Prove that `angleBAC=angleBDC`.

Explanation

To prove that \( \angle BAC = \angle BDC \) for the triangles ACB and ADB situated on opposite sides of the common hypotenuse AB, we will follow these steps:

### Step-by-Step Solution:

1. **Draw the Diagram**:
- Start by drawing the line segment AB, which will be the common hypotenuse.
- Construct two right-angled triangles ACB and ADB such that they are on opposite sides of AB.
- Label the points: A, B, C, and D where A and B are the endpoints of the hypotenuse, and C and D are the vertices of the right-angled triangles.
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