If ABC is an equilateral triangle inscribed in a circle and P be any point on the minor arc BC which does not coincide with B or C, then prove that PA is angle bisector of `angleBPC`.

Explanation

To prove that line segment PA is the angle bisector of angle BPC in an equilateral triangle ABC inscribed in a circle, follow these steps:

### Step-by-Step Solution:

1. **Draw the Figure**: Start by drawing an equilateral triangle ABC inscribed in a circle with center O. Mark point P on the minor arc BC, ensuring that P does not coincide with points B or C.

2. **Identify Angles**: We need to prove that PA bisects angle BPC. Let angle BPC be divided into two angles: angle 1 (∠APB) and angle 2 (∠APC).

...