The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is

Options

A. 15
B. 25
C. 35
D. 40

Explanation

To solve the problem step by step, let's break it down clearly:

### Step 1: Understand the Given Information
We are given:
- The width of each class = 5
- The lower class limit of the lowest class = 10
- The number of classes = 5

### Step 2: Determine the Lower and Upper Class Limits of the First Class
The first class can be represented as:
- Lower class limit (x) = 10
- Upper class limit (y) = x + width = 10 + 5 = 15

So, the first class is 10 to 15.

### Step 3: Determine the Subsequent Classes
Since the classes are continuous and each has a width of 5, we can find the remaining classes:
1. First class: 10 to 15
2. Second class: 15 to 20
3. Third class: 20 to 25
4. Fourth class: 25 to 30
5. Fifth class: 30 to 35

### Step 4: Identify the Upper Class Limit of the Highest Class
The highest class is the fifth class, which is:
- Lower class limit = 30
- Upper class limit = 35

### Conclusion
Therefore, the upper class limit of the highest class is **35**.

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