If `m` is the mid-point and `l` is the upper limit of a class in a continuous frequency distribution, then lower class limit of the class is

Options

A. `2m + l`
B. `2m-l`
C. `m-l`
D. `m-2l`

Explanation

To find the lower class limit of a class in a continuous frequency distribution when given the midpoint (m) and the upper limit (l), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Formula for Midpoint:**
The midpoint (m) of a class is calculated using the formula:
\[ m = \frac{l + x}{2} \]
where \( l \) is the upper class limit and \( x \) is the lower class limit.

2. **Rearrange the Formula:**
To find the lower class limit \( x \), we need to rearrange the formula. Start by multiplying both sides by 2:
\[ 2m = l + x \]

3. **Isolate the Lower Class Limit:**
Next, isolate \( x \) by subtracting \( l \) from both sides:
\[ x = 2m - l \]

4. **Conclusion:**
Thus, the lower class limit \( x \) is given by the formula:
\[ x = 2m - l \]

### Final Answer:
The lower class limit of the class is \( 2m - l \).