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If the mean of the observation x, x+3, x...

If the mean of the observation `x``,` `x+3``,` `x+5``,` `x+7` and `x+10` is `9``,` then mean of the last three observations is

A

`101/3`

B

`102/3`

C

`11``1/3`

D

`112/3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find the mean of the last three observations given that the mean of the five observations is 9. ### Step 1: List the Observations The observations given are: - \( x \) - \( x + 3 \) - \( x + 5 \) - \( x + 7 \) - \( x + 10 \) ### Step 2: Write the Mean Formula The mean of these observations is given by the formula: \[ \text{Mean} = \frac{\text{Sum of observations}}{\text{Number of observations}} \] Here, the number of observations is 5. ### Step 3: Set Up the Equation According to the problem, the mean is 9. Thus, we can set up the equation: \[ 9 = \frac{x + (x + 3) + (x + 5) + (x + 7) + (x + 10)}{5} \] ### Step 4: Simplify the Equation Now, let's simplify the sum in the numerator: \[ x + (x + 3) + (x + 5) + (x + 7) + (x + 10) = 5x + (3 + 5 + 7 + 10) = 5x + 25 \] So, we can rewrite the equation as: \[ 9 = \frac{5x + 25}{5} \] ### Step 5: Multiply Both Sides by 5 To eliminate the fraction, multiply both sides by 5: \[ 9 \times 5 = 5x + 25 \] This simplifies to: \[ 45 = 5x + 25 \] ### Step 6: Solve for \( x \) Now, isolate \( x \): \[ 45 - 25 = 5x \] \[ 20 = 5x \] \[ x = \frac{20}{5} = 4 \] ### Step 7: Find the Last Three Observations Now that we have \( x = 4 \), we can find the last three observations: - \( x + 5 = 4 + 5 = 9 \) - \( x + 7 = 4 + 7 = 11 \) - \( x + 10 = 4 + 10 = 14 \) So, the last three observations are 9, 11, and 14. ### Step 8: Calculate the Mean of the Last Three Observations Now, we need to find the mean of these last three observations: \[ \text{Mean} = \frac{9 + 11 + 14}{3} \] Calculating the sum: \[ 9 + 11 + 14 = 34 \] So, the mean is: \[ \text{Mean} = \frac{34}{3} \] ### Step 9: Final Answer The mean of the last three observations is: \[ \frac{34}{3} = 11 \frac{1}{3} \]
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