if `tantheta+sectheta=l ` then prove that `sectheta=(l^2+1)/(2l)`

Explanation

To prove that if \( \tan \theta + \sec \theta = l \), then \( \sec \theta = \frac{l^2 + 1}{2l} \), we can follow these steps:

### Step 1: Start with the given equation
We are given:
\[ \tan \theta + \sec \theta = l \]

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