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Find the most general value of theta sa...

Find the most general value of ` theta` satisfyingn the equation `tantheta=-1 and costheta=(1 )/(sqrt(2))`.

A

`theta= 2npi+(7pi)/(4)`.

B

`theta= npi+(7pi)/(4)`.

C

`theta= 2npi+(pi)/(4)`.

D

none of these

Text Solution

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The correct Answer is:
To solve the problem of finding the most general value of \( \theta \) satisfying the equations \( \tan \theta = -1 \) and \( \cos \theta = \frac{1}{\sqrt{2}} \), we can follow these steps: ### Step 1: Analyze the equation \( \tan \theta = -1 \) The tangent function is negative in the second and fourth quadrants. The specific angles where \( \tan \theta = -1 \) are: - \( \theta = \frac{3\pi}{4} \) (in the second quadrant) - \( \theta = \frac{7\pi}{4} \) (in the fourth quadrant) ### Step 2: Write the general solutions for \( \tan \theta = -1 \) The general solutions for \( \tan \theta = -1 \) can be expressed as: \[ \theta = n\pi - \frac{\pi}{4} \] where \( n \) is any integer. ### Step 3: Analyze the equation \( \cos \theta = \frac{1}{\sqrt{2}} \) The cosine function is positive in the first and fourth quadrants. The specific angles where \( \cos \theta = \frac{1}{\sqrt{2}} \) are: - \( \theta = \frac{\pi}{4} \) (in the first quadrant) - \( \theta = \frac{7\pi}{4} \) (in the fourth quadrant) ### Step 4: Write the general solutions for \( \cos \theta = \frac{1}{\sqrt{2}} \) The general solutions for \( \cos \theta = \frac{1}{\sqrt{2}} \) can be expressed as: \[ \theta = 2n\pi \pm \frac{\pi}{4} \] where \( n \) is any integer. ### Step 5: Find the common solutions Now, we need to find the common solutions from both equations: 1. From \( \tan \theta = -1 \): \[ \theta = n\pi - \frac{\pi}{4} \] 2. From \( \cos \theta = \frac{1}{\sqrt{2}} \): \[ \theta = 2n\pi + \frac{\pi}{4} \quad \text{and} \quad \theta = 2n\pi - \frac{\pi}{4} \] The common solution from both sets is: - For \( \theta = 2n\pi - \frac{\pi}{4} \) (from cosine) and \( \theta = n\pi - \frac{\pi}{4} \) (from tangent), we can see that both share the term \( -\frac{\pi}{4} \). ### Step 6: Write the final general solution Thus, the most general values of \( \theta \) satisfying both equations can be expressed as: \[ \theta = 2n\pi - \frac{\pi}{4} \quad \text{and} \quad \theta = 2n\pi + \frac{7\pi}{4} \] where \( n \) is any integer. ### Final Answer: The most general values of \( \theta \) are: \[ \theta = 2n\pi - \frac{\pi}{4} \quad \text{and} \quad \theta = 2n\pi + \frac{7\pi}{4} \]

To solve the problem of finding the most general value of \( \theta \) satisfying the equations \( \tan \theta = -1 \) and \( \cos \theta = \frac{1}{\sqrt{2}} \), we can follow these steps: ### Step 1: Analyze the equation \( \tan \theta = -1 \) The tangent function is negative in the second and fourth quadrants. The specific angles where \( \tan \theta = -1 \) are: - \( \theta = \frac{3\pi}{4} \) (in the second quadrant) - \( \theta = \frac{7\pi}{4} \) (in the fourth quadrant) ### Step 2: Write the general solutions for \( \tan \theta = -1 \) ...
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