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If secxcos5x+1=0 , where 0ltxle(pi)/(2)...

If `secxcos5x+1=0 `, where `0ltxle(pi)/(2)`, then find the value of x.

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To solve the equation \( \sec x \cos 5x + 1 = 0 \) for \( 0 < x \leq \frac{\pi}{2} \), we can follow these steps: ### Step 1: Rewrite the equation Starting with the equation: \[ \sec x \cos 5x + 1 = 0 \] We can rewrite \( \sec x \) as \( \frac{1}{\cos x} \): ...
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