Show that the middle term in the expansion `(x-1/x)^(2n)i s` `(1. 3. 5 (2n-1))/n(-2)^n` .

Explanation

To find the middle term in the expansion of \((x - \frac{1}{x})^{2n}\), we will follow these steps:

### Step 1: Identify the Middle Term
The middle term in the expansion of \((x + y)^n\) is given by the formula \(T_{r+1} = \binom{n}{r} x^{n-r} y^r\). For an even \(n\), the middle term is \(T_{n/2 + 1}\). In our case, since \(n = 2n\), the middle term will be \(T_{n + 1}\).

**Hint:** Remember that for an expression raised to an even power, the middle term is at position \(n/2 + 1\).

### Step 2: Write the General Term
...