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If the seventh term from the beginning and end in the binomial expansion of `(2 3+1/(3 3))^n ,""` are equal, find `ndot`

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To solve the problem, we need to find the value of \( n \) such that the seventh term from the beginning and the seventh term from the end in the binomial expansion of \( (23 + \frac{1}{33})^n \) are equal. ### Step-by-step Solution: 1. **Identify the terms in the binomial expansion:** The general term \( T_{r+1} \) in the binomial expansion of \( (x + y)^n \) is given by: \[ T_{r+1} = \binom{n}{r} x^{n-r} y^r ...
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