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lim(xrarr(pi))(sinx)/(x-pi) is equal to...

`lim_(xrarr(pi))(sinx)/(x-pi)` is equal to

A

1

B

2

C

`-1`

D

`-2`

Text Solution

Verified by Experts

The correct Answer is:
C
Given, `lim_(xto(pi))(sinx)/(x-pi)` `[therefore sintheta=sin(pi-theta)]`
`=-lim_(xto(pi))(sin(pi-x))/(pi-x)=-1` `[therefore lim_(xto0)(sinx)/(x)=1 " and " xto0 rArr xto(pi)]`
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