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If y=1+ x/(1!)+x^2/(2!)+x^3/(3!)+......,...

If `y=1+ x/(1!)+x^2/(2!)+x^3/(3!)+......,` then `(dy)/(dx)`

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To solve the problem, we need to differentiate the given function \( y \) with respect to \( x \). The function is defined as: \[ y = 1 + \frac{x}{1!} + \frac{x^2}{2!} + \frac{x^3}{3!} + \ldots \] ### Step-by-Step Solution: ...
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