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If arg(z-1)=arg(z+3i), then find (x-1):y...

If `arg(z-1)=arg(z+3i)`, then find `(x-1):y`, where `z=x+iy`.

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To solve the problem where \( \arg(z-1) = \arg(z+3i) \) and \( z = x + iy \), we will follow these steps: ### Step 1: Substitute \( z \) in the argument equation We start by substituting \( z = x + iy \) into the equation: \[ \arg(z - 1) = \arg(z + 3i) \] This gives us: ...
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