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If one end of a diameter of the circle x...

If one end of a diameter of the circle `x^(2) + y^(2) -4x-6y +11=0` is (3, 4), then find the coordinates of the other end of the diameter.

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To find the coordinates of the other end of the diameter of the circle given by the equation \(x^2 + y^2 - 4x - 6y + 11 = 0\) and one end of the diameter at the point \((3, 4)\), we can follow these steps: ### Step 1: Rewrite the Circle Equation First, we need to rewrite the given equation of the circle in standard form. We do this by completing the square for both \(x\) and \(y\). The given equation is: \[ x^2 + y^2 - 4x - 6y + 11 = 0 ...
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