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Find the equation of the circle which pa...

Find the equation of the circle which passes through the points `(2,3),(4,5)` and the centre lies on the straight line `y-4x+3=0.`

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To find the equation of the circle that passes through the points (2, 3) and (4, 5) with its center lying on the line \(y - 4x + 3 = 0\), we can follow these steps: ### Step 1: General Equation of the Circle The general equation of a circle can be expressed as: \[ x^2 + y^2 + 2gx + 2fy + c = 0 \] where \((h, k) = (-g, -f)\) is the center of the circle. ...
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